9x^2+88x+63=0

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Solution for 9x^2+88x+63=0 equation: 



9x^2+88x+63=0

a = 9; b = 88; c = +63;
Δ = b2-4ac
Δ = 882-4·9·63
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-74}{2*9}=\frac{-162}{18}
=-9
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+74}{2*9}=\frac{-14}{18}
=-7/9
$

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